-0.35x^2-0.5x+0.05=0

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Solution for -0.35x^2-0.5x+0.05=0 equation: 



-0.35x^2-0.5x+0.05=0

a = -0.35; b = -0.5; c = +0.05;
Δ = b2-4ac
Δ = -0.52-4·(-0.35)·0.05
Δ = 0.32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.5)-\sqrt{0.32}}{2*-0.35}=\frac{0.5-\sqrt{0.32}}{-0.7}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.5)+\sqrt{0.32}}{2*-0.35}=\frac{0.5+\sqrt{0.32}}{-0.7}
$

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